Question #194158

1) A 40-m vertical column of fluid with density of 1872 kg/m3 is located where g = 9.65 g/m2. Find the pressure at the base of the column.


2) Two liquids of different densities (ρ1 = 1500 kg/m3 , ρ2 = 500 kg/m3) are poured together into a 120-liter tank, filling it. If the resulting density of the mixture is 820 kg/m3, find the respective amounts of liquids used. Also find the weight of the mixture; local g= 9.675 m/s2.


3) If a pump discharges 284 liters per minute of water whose density is 985 kg/m3, find (a)the mass flow rate in kg/min, (b) the total time required to fill a vertical tank 3 m in diameter and 4 m high.


6)Fahrenheit and a Celsius thermometer are both immersed in a fluid and indicate identical numerical readings. What is the temperature of the fluid expressed as °R and as °K?


1
Expert's answer
2021-05-17T18:34:42-0400

1) h=40 mρ=1872 kg/m3g=9.65 m/s21)\ h = 40\ m\\\rho = 1872\ kg/m³\\ g = 9.65\ m/s²


P=ρgh=1872×9.65×40=722592PaP = \rho gh = 1872× 9.65×40 = 722592 Pa



2) ρ1=1500 kg/m3ρ2=500 kg/m3V=120 Lρr=820 kg/m3g=9.675 m/s22)\ \rho_1 = 1500\ kg/m³\\ \rho_2 = 500\ kg/m³\\ V = 120\ L\\ \rho_r = 820\ kg/m³\\ g = 9.675\ m/s²


ρ=m/Vmr=820×120=98400 kg1500x+500(120x)=984001500x+60000500x=984001000x=38400x=38.4 L\rho = m/V\\ m_r = 820 × 120 = 98400\ kg\\ 1500x + 500(120-x)= 98400\\ 1500x + 60000- 500x = 98400\\ 1000x = 38400\\ x = 38.4\ L

\therefore 38.4 L of the first liquid is used and 81.6 L of the second liquid is used.



3) V/t=284 L per minuteρ=985 kg/m33)\ V/t= 284\ L\ per\ minute\\ \rho = 985\ kg/m³\\


(a) m/t=V/t×ρ=284×985=279740 kg/min(b) V=πr2h=π(3/2)2×4=28.27m3m=28.27×985=27846 kgt=27846/279740=0.0995 min=5.97 sec(a)\ m/t = V/t ×\rho= 284× 985 =279740\ kg/min\\ (b) \ V = πr²h = π(3/2)²× 4 = 28.27m³\\ m = 28.27 ×985 = 27846\ kg\\ t = 27846/279740 = 0.0995\ min = 5.97\ sec


6)\The Fahrenheit and Celsius scales have one point at which they intersect. They are equal at -40 °C and -40 °F


K=°C+273.15=40+273.15=233.15K°R=°F+459.67=40+459.67=419.67°RK = °C + 273.15 = -40+ 273.15= 233.15K\\ °R = °F + 459.67= -40+ 459.67 = 419.67°R

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