Calculate the temperature of a fluid when both a Fahrenheit and a Celsius thermometer are immersed in it, under the following conditions :a) the numerical reading is identical in both thermometers? b) the Fahrenheit reading is numerically twice that of the Celsius reading. Express the values in °R and °K.
The connection between two temperature units is following
"\\displaystyle T_C = (T_F -32) \\cdot \\frac{5}{9}"
(a) let's denote X the number we are looking for
"\\displaystyle X = \\frac{5}{9}(X-32) = \\frac{5}{9} X -17.7778"
"\\displaystyle \\frac{4}{9} X = -17.7778"
"X =-40"
Answer: "T_F = -40^\\circ F, T_C = -40^\\circ C, T=233.15 K"
(b) let's denote Celsius temperature as X
"\\displaystyle X = \\frac{5}{9}(2X-32) = \\frac{10}{9} X -17.7778"
"\\displaystyle -\\frac{1}{9} X = -17.7778"
"X=160"
Answer: "T_F = 320^\\circ F, T_C = 160^\\circ C, T=433.15 K"
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