A copper wire has a resistance of 5 Ω at 20°C. What is its resistance if the temperature. Changed to 75°C
Given,
Resistance of the copper wire (Ro)=5Ω(R_o)=5\Omega(Ro)=5Ω
T1=20∘CT_1= 20^\circ CT1=20∘C
R2=?R_2=?R2=?
T2=75∘CT_2=75^\circ CT2=75∘C
R=Ro(1+αdT)R=R_o(1+\alpha dT)R=Ro(1+αdT)
temperature coefficient for copper (α)=+0.39×10−2Ω/∘C(\alpha)= +0.39\times 10^{-2}\Omega/^\circ C(α)=+0.39×10−2Ω/∘C
Now, R2=5(1+0.39×10−2×(75−20))R_2=5(1+0.39\times 10^{-2}\times (75-20))R2=5(1+0.39×10−2×(75−20))
⇒R2=5(1+0.39×10−2×55)Ω\Rightarrow R_2=5(1+0.39\times 10^{-2}\times 55)\Omega⇒R2=5(1+0.39×10−2×55)Ω
⇒R2=5×1.21Ω\Rightarrow R_2 =5\times 1.21\Omega⇒R2=5×1.21Ω
⇒R2=6.05Ω\Rightarrow R_2 = 6.05 \Omega⇒R2=6.05Ω
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