Air is contained in a rigid container has a pressure of 0.5
bar vacuum. If the atmospheric pressure is 740 mm Hg, and
the density of mercury is 13.59 g/cm3. Determine the absolute pressure of the container in bar.
Answer
Absolute pressure is given
Absolute pressure=atmospheric pressure+gauge pressure
Absolute pressure
"P_{atm}=\\rho . g. h"
"=13.59\\times0.001\\times9.81\\times74\\\\=0.9865bar"
Threfore absolute pressure
"P_a=P_{atm}+P_g"
"=0.9865+(-0.5) \\\\=0.4865bar"
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