Question

Air is contained in a rigid container has a pressure of 0.5

bar vacuum. If the atmospheric pressure is 740 mm Hg, and

the density of mercury is 13.59 g/cm3. Determine the absolute pressure of the container in bar.

Answer 1

Answer

Absolute pressure is given

Absolute pressure=atmospheric pressure+gauge pressure

Absolute pressure

$P_{atm}=\rho . g. h$

$=13.59\times0.001\times9.81\times74\\=0.9865bar$

Threfore absolute pressure

$P_a=P_{atm}+P_g$

$=0.9865+(-0.5) \\=0.4865bar$