Steam at 100 bar, 3200 C expands isothermally in a cylinder behind a piston to a pressure of 10 bar. Solve for the work done per kilogram of steam.
W=mMRTlnp1p2→W/m=RTMlnp1p2=W=\frac{m}{M}RT\ln\frac{p_1}{p_2}\to W/m=\frac{RT}{M}\ln\frac{p_1}{p_2}=W=MmRTlnp2p1→W/m=MRTlnp2p1=
=8.31⋅5930.018ln10010=630375 (J/kg)=\frac{8.31\cdot 593}{0.018}\ln\frac{100}{10}=630375\ (J/kg)=0.0188.31⋅593ln10100=630375 (J/kg) . Answer
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