Question

a 2 kg iron block is taken from a furnace where its temparature was 672 degree celsius and placed a large block of ice at 0 degree celsius.Assuming that heat given up by iron is used to melt the ice , how much ice is melted if specific heat capacity for iron is 450 jkg-1k-1

Answer 1

A 2 kg iron block is taken from a furnace where its temperature was 672 degree celsius and placed a large block of ice at 0 degree celsius. Assuming that heat given up by iron is used to melt the ice, how much ice is melted if specific heat capacity for iron is 450 jkg-1k-1

Solution

$$Q_{iron} = c * m * (t_2 - t_1)$$ $$Q_{ice} = L * M$$ $$M = \frac{c * m * (t_2 - t_1)}{L}$$

L is specific heat of melting (335 kJ/kg)

$$M = 1.8 \text{ kg of ice}$$