Question

in charles law if there is spontaneous from v1 to v2 then what effect on temperature and pressure?

Answer 1

Question #16029

Charles law is for $p = \text{const}$ . Hence, $\frac{V}{T} = \text{const}$ , and $\frac{V_1}{T_1} = \frac{V_2}{T_2}$ , which gives $T_2 = T_1 \frac{V_2}{V_1}$ , and the pressure remains constant. So, if the volume increased, the temperature increased too, and vice versa.