Answer to Question #160597 in Molecular Physics | Thermodynamics for Nama glory

Question

When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.08 oC is allowed to expand to 3.00 times its original volume, its final pressure is 1.07 x 10^6 Pa. What is its final temperature?

Answer 1

Answer

Using idea gas equation

PV=nRT

So final temperature

$T_2=\frac{T_1P_2V_2}{P_1V_1}$

$=\frac{298.23\times 1.07\times10^6\times3V_1}{5\times10^6\times V_1}$

=191.36K