Question #160597
When a certain gas under a pressure of 5.00 x 10^6 Pa at 25.08 oC is allowed to expand to 3.00 times its original volume, its final pressure is 1.07 x 10^6 Pa. What is its final temperature?
1
Expert's answer
2021-02-10T13:14:00-0500

Answer

Using idea gas equation

PV=nRT

So final temperature

T2=T1P2V2P1V1T_2=\frac{T_1P_2V_2}{P_1V_1}

=298.23×1.07×106×3V15×106×V1=\frac{298.23\times 1.07\times10^6\times3V_1}{5\times10^6\times V_1}

=191.36K


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS