Question

Radiation intensity of a dipole depends strongly on frequency. If at a frequency f, the intensity of radiation is 'I'. Then at a frequency of f/2, the intensity will be

Answer 1

We know that radiation intensity of dipole is directly proportional to the power four of frequency i.e

$$I=kf^4$$

Where I is intensity and f is frequency.If frequency become f/2 ,then intensity become

$$I'=k\bigg(\frac{f}{2}\bigg)^4\\I'=k\bigg(\frac{f^4}{16}\bigg)\\I'=\bigg(\frac{I}{16}\bigg)$$

This Radiation intensity of dipole become I/16.