A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the half power beamwidth
Answer
half power beam width is
HPBW=BWFN/2="\\frac{2\\lambda}{nd2}=\\frac{\\lambda}{nd}"
According to question
"\\frac{\\lambda}{d}=20"
"HPBW=\\frac{20}{10}=2^\u00b0"
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