Question

A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the half power beamwidth

Answer 1

Answer

half power beam width is

HPBW=BWFN/2=$\frac{2\lambda}{nd2}=\frac{\lambda}{nd}$

According to question

$\frac{\lambda}{d}=20$

$HPBW=\frac{20}{10}=2^°$