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Answer to Question #1479 in Molecular Physics | Thermodynamics for Michael
Question #1479
How much heat is lost by 5.0 grams of water if the temperature falls from 30 degrees Celsius to 26 degrees Celsius. The specific heat of water measured in joules is 4.184 Joules/g˚C
Expert's answer
The amount of heat lost is
Q = CmΔT = 4.184[J/gC]*5[g]*(26-30)[C] = -83.68 J
Q = CmΔT = 4.184[J/gC]*5[g]*(26-30)[C] = -83.68 J
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