2 litres of mercury at 80 deg.Celsius is pushed into a plastic bucket containing 10 litres of mercury at a temperature "T".if the final temperature of the mixture is 30 degree Celsius ,what is the value of "T".(neglect any heat loss to environment)
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Expert's answer
2011-02-03T07:26:07-0500
We can use the heat balance equation Cm m1 ΔT1 = Cm m2 ΔT2 ΔT1 = 80 - 30 =50
ΔT2 = 30 - T
m1/m2 = 2/10 = 0.2 Thus
(30-T) = 50*0.2 = 10 T = 30-10 = 20 C. Answer: T= 20 C.
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