Answer to Question #137015 in Molecular Physics | Thermodynamics for Viccy

Question

Write down expression of work done in isothermal process.

Answer 1

Solution:

W = integral of p dV.

If we are working with an ideal gas, then

p =$\dfrac{nRT}{V}$ and

W = integral of nRT $\dfrac{dV}{V}$= nRT ln($\dfrac{V_{2}}{V_{1}}$).

If we are not working with an ideal gas, we will have to supply more information.

Another possible answer is W = Q (because there is no internal energy change), but that's probably not what they're after.