Answer to Question #136628 in Molecular Physics | Thermodynamics for Defiya

Question

A faulty thermometer reads maelting point -10degree Celsius .it reads 60 degree c in place of 50 degree c .what is the temperature of boiling point of water on this scale ?

Answer 1

The lower fixed point on the wrong scale is -10 ºC. Let n be the number of divisions between upper and lower fixed points on this scale. If Θ is the reading on this scale, then,

$\frac{C – 0}{100} = \frac{Θ-(-10)}{n}$

When C = 50 ºC, Θ = 60 ºC

$\frac{50 – 0}{100} = \frac{60-(-10)}{n} = \frac{70}{n}$

$n = 70 \times \frac{100}{50} = 140$

$\frac{C – 0}{100} = \frac{Θ-(-10)}{140}$

On the Celsius scale, boiling point of water is 100 ºC

$\frac{100 – 0}{100} = \frac{Θ-(-10)}{140}$

Θ = 140 – 10 = 130 ºC

Answer: 130 ºC