Number of ways to choose 3 books for the first student out of 12:C312
Number of ways to choose 3 books for the second student out of 9:C39
Number of ways to choose 3 books for the third student out of 6:C36
Number of ways to choose 3 books for the fourth student out of 3:1
Total options:
"C^3_{12}\\cdot C^3_9\\cdot C^3_6\\cdot 1=\\frac{12!\\cdot9!\\cdot6!}{3!\\cdot9!\\cdot3!\\cdot6!\\cdot3!\\cdot3!}=369600"
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