125 ft/s=38.1 m/s
1000 ft/s=304.8 m/s
P1=KE1m=v122=38.122≈726J/kg=0.726kJ/kgP_1=\frac{KE_1}{m}=\frac{v_1^2}{2}=\frac{38.1^2}{2}\approx726J/kg=0.726kJ/kgP1=mKE1=2v12=238.12≈726J/kg=0.726kJ/kg
P2=KE2m=v222=304.822≈92903J/kg=92.903kJ/kgP_2=\frac{KE_2}{m}=\frac{v_2^2}{2}=\frac{304.8^2}{2}\approx92903J/kg=92.903kJ/kgP2=mKE2=2v22=2304.82≈92903J/kg=92.903kJ/kg
(a) 0.726 (kJ/kg)=242.73 (ft-lbf/lb)=0.312BTU/lb
(b) 92.903 (kJ/kg)=31073.44 (ft-lbf/lb)=39.941 (BTU/lb)
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Dear visitor, please use panel for submitting new questions
Where did you get the 242.73 and 31073.44?