Answer to Question #99899 in Mechanics | Relativity for Fahad

Question #99899
A dipole is consisting of an electron and proton, 4e-10 m apart. compute the electric field at a distance of 2e-8 m on a line making perpendicular with the dipole exist from the centre of the dipole?
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Expert's answer
2019-12-11T10:30:03-0500


For the situation shown above, we can first calculate the distance from the charges to the considered point:


d=(41010)2+(2108)2=2108 m.d=\sqrt{(4\cdot10^{-10})^2+(2\cdot10^{-8})^2}=2\cdot10^{-8}\text{ m}.

Now calculate the magnitude of the vectors of the electric field lines at the considered point:


E=E=E+=ke/d2.E=E_-=E_+=ke/d^2.

However, the field has two components: vertical and horizontal. The horizontal component of the total resultant field is


Ex=E+ cosα+E cosα=2E cosα==179751036 V/m.E_x=E_+\text{ cos}\alpha+E_-\text{ cos}\alpha=2E\text{ cos}\alpha=\\ =179751036\text{ V/m}.

The vertical component of the resultant field is


Ey=E+ sinαE sinα=0.E_y=E_+\text{ sin}\alpha-E_-\text{ sin}\alpha=0.


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Comments

Fahad
05.12.19, 17:45

Please send details about the answer for example:k=9x10^9....

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