Question #99349
Ali bicycles to a place 20km away. John's route to the same place is 4km longer but he rides 2km/h faster than Ali and gets their 5mins later. What are their speeds?
1
Expert's answer
2019-11-25T10:00:31-0500

Assume Ali's speed is vv , then John's speed is v+2v + 2 , km/h.


Time spent: by Ali is 20v\cfrac{20}v , by John is 20+4v+2\cfrac{20 + 4}{v + 2} ., h.


Given that John spent 5 minutes (1/12 hour) more, we can make the equation


20v+112=20+4v+2\qquad \cfrac{20}{v} + \cfrac{1} {12} = \cfrac{20+4}{v + 2}


To get rid of fractions we multiply the left and right sides of the equation by 12v(v+2)12v(v+2)


2012(v+2)+1v(v+2)=2412v\qquad 20 * 12 (v+2) + 1*v(v+2) = 24*12v


v246v+480=0\qquad v^2 - 46v + 480 = 0


(v16)(v30)=0\qquad (v -16)(v - 30) = 0


v1=16, v2=30\qquad \underline{v_1 = 16}, \space \underline{v_2 = 30}


The problem has two solutions: 

1) Ali's speed is 16 km/h, John's speed is 18 km/h.

2) Ali's speed is 30, John's speed is 32.


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Comments

Oyarebu
28.11.19, 14:38

Please can u work in m/s. Sorry I didn't add that part sooner. And how did u get to divide by 12v(v + 2)

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