part 1
Potential energy:
E=mgh=(5)(9.8)(10)=490 J
KE=0.5mv2=0.5(5)(8)2=160 J
P=mv=(5)(8)=40skgm The impulse the mass transfers to the ground:
I=P=40skgm The force:
F=tI=440=10 N part 2
W=mgh=(5)(9.8)(2)=98 J
E=mgh′=0.5mg2t2
E=0.5(5)((11)(9.8))2=29000 J=29 kJ
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