Question #99136
part 1- A mass of 5KG is on top of a building of heights 10M calculate its potential energy the mass then falls at a speed of 8M/S in 4 seconds find its KE and momentum P what is the force and impulse the mass transfers to the ground

part-2- For the above problem find the work done by gravity if the mass falls a distance of 2 meters if the mass falls for 11 seconds what is the energy expanded by this force?
1
Expert's answer
2019-11-22T10:57:26-0500

part 1


Potential energy:


E=mgh=(5)(9.8)(10)=490 JE=mgh=(5)(9.8)(10)=490\ J


KE=0.5mv2=0.5(5)(8)2=160 JKE=0.5mv^2=0.5(5)(8)^2=160\ J

 

P=mv=(5)(8)=40kgmsP=mv=(5)(8)=40\frac{kgm}{s}

​ The impulse the mass transfers to the ground:


I=P=40kgmsI=P=40\frac{kgm}{s}

 The force:


F=It=404=10 NF=\frac{I}{t}=\frac{40}{4}=10\ N

part 2



W=mgh=(5)(9.8)(2)=98 JW=mgh=(5)(9.8)(2)=98\ J

E=mgh=0.5mg2t2E=mgh'=0.5mg^2t^2

E=0.5(5)((11)(9.8))2=29000 J=29 kJE=0.5(5)((11)(9.8))^2=29000\ J=29\ kJ


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