(a) Let q1 be charge on droplet
Gravitational force due to weight = electrostatic force due to electric field
So,
q1E=mg
q1=Emg=5.92×1042.93×10−15×9.8=4.85×10−19 C
(b) Let q2 be charge on this droplet
then according to question,
s=ut+21at2.153=0.5a×(.2752)ora=4.05 m sec−2 balancing force,
ma=mg−q2E
m=2.93×10−15 kgE=5.92×104
2.93×10−15×4.05=2.93×10−15×9.8−q2×5.92×104
Orq2=2.84×10−19 C
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