The Newton's law for viscosity
F=ηA∂x∂v
where F - force, has the dimension [LMT−2], A - area of contact, hast the dimension [L2] and ∂x∂v - velocity gradient has the dimension [T−1] (because v has the dimension [LT−1] and x has the dimension [L] ). Let η has the dimension [X]. Then, using the Newton's law for viscosity
[LMT−2]=[X][L2][T−1] Thus
[X]=[ML−1T−1]
Comments