Question #96521
The viscous charge F between two layers of liquid with specific area of contact A in a region of velocity gradient dv/dt is given by F = integration sign A dv ÷dt where the constant is the cofficient of the viscosity .what is the dimension of the constant.
1
Expert's answer
2019-10-15T06:19:22-0400

The Newton's law for viscosity


F=ηAvxF = \eta A{{\partial v} \over {\partial x}}


where FF - force, has the dimension [LMT2][{\rm{LM}}{{\rm{T}}^{ - 2}}], AA - area of contact, hast the dimension [L2][{{\rm{L}}^2}] and vx{{\partial v} \over {\partial x}} - velocity gradient has the dimension [T1]{\rm{[}}{{\rm{T}}^{ - 1}}] (because vv has the dimension [LT1][{\rm{L}}{{\rm{T}}^{ - 1}}] and xx has the dimension [L][{\rm{L}}] ). Let η\eta has the dimension [X][X]. Then, using the Newton's law for viscosity


[LMT2]=[X][L2][T1][{\rm{LM}}{{\rm{T}}^{ - 2}}] = [X][{{\rm{L}}^2}][{{\rm{T}}^{ - 1}}]

Thus


[X]=[ML1T1][X] = [{\rm{M}}{{\rm{L}}^{ - 1}}{{\rm{T}}^{ - 1}}]


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