Answer to Question #95733 in Mechanics | Relativity for stefanie

Question

A 28.0-kg block is initially at rest on a horizontal surface. A horizontal force of 80.0 N is required to set the block in motion, after which a horizontal force of 57.0 N is required to keep the block moving with constant speed.
(a) Find the coefficient of static friction between the block and the surface.
(b) Find the coefficient of kinetic friction between the block and the surface.

Answer 1

Let F_a be force applied to block, m be mass of the block, F_k and F_s be kinetic and static friction respectively, k_k and k_s be coefficients of kinetic and static friction.

a)To move object from the rest force applied to block must overcome static friction force,

therefore

$F_a=F_s=k_s\cdot m\cdot d,\$

$k_s=\frac{F_a}{m\cdot g}=\frac{80}{28\cdot 9.8}\approx0.29$

b) Since acceleration of the block is zero

$F_a=F_k=k_k\cdot m\cdot g,$

$k_k=\frac{F_a}{m\cdot g}=\frac{57}{28\cdot 9.8}\approx0.2$

Answer: a)0.29, b) 0.2.