Solution:
Let's use the law of conservation of energy. Potential energy of textbook on the ground is equal to zero, and kinetic energy of the textbook when it reaches the maximum height is also equal to zero. So kinetic energy of the book on the ground is equal to it's potential energy in the highest point:
"\\frac{m\\upsilon^2}{2}=mgh"
"\\upsilon=\\sqrt{2gh}=\\sqrt{2\\cdot{}9.8\\cdot{}12}=15" m/s.
Answer:
15 m\s.
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