The ball is thrown upwards and returns in 6 seconds, so it spends half the time, or 2 seconds, going up, and another 2 seconds coming down.
The maximum height h is equal to:
At max height, v=0.
In this case, we can write
"0=v_0-9.8\\times 2 (2)"
Using the formula (2) we get: v0=19.6 m/s
Using the formula (1) we get:
Using the formula (3) we get: h(2)=19.6 m.
Answer:
19.6 m
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