Answer to Question #86923 in Mechanics | Relativity for MESHACH

Question

find the angle of projection at which the horizontal range is twice the maximum height of the projectile

Answer 1

$a_x=2a_y$

$\tan \alpha = \frac{a_y}{a_x}$

$\tan \alpha = \frac{1}{2}$

$\alpha \approx 26.6 ^\circ$

Answer: $26.6 ^\circ$