Answer to Question #86923 in Mechanics | Relativity for MESHACH

Mechanics | Relativity

Question #86923

find the angle of projection at which the horizontal range is twice the maximum height of the projectile

Expert's answer

"a_x=2a_y"

"\\tan \\alpha = \\frac{a_y}{a_x}"

"\\tan \\alpha = \\frac{1}{2}"

"\\alpha \\approx 26.6 ^\\circ"

Answer: "26.6 ^\\circ"

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