Answer to Question #86396 in Mechanics | Relativity for Manisha nayak
Calculate the area of a triangle whose vertices are given by (3,-1,2),(1,-1,2),(4,-2,1)
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2019-03-15T12:45:45-0400
Let
A=(3,−1,2),B=(1,−1,2),C=(4,−2,1)So
AB=(1−3,−1−(−1),2−2)=(−2,0,0)AC=(4−3,−2−(−1),1−2)=(1,−1,−1)
The vector product
[AB×AC]=∣∣i^−21j^0−1k^0−1∣∣=−2j^+2k^ The area of the triangle
A=21∣[AB×AC]∣=21(−2)2+22=2
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