Question #86392
A man carries a load of 50 kg to a height of 15m in 5 minutes. Calculate A) the work done, B)the power extended
1
Expert's answer
2019-03-15T12:45:28-0400

a) By the definition of the work, we have:


W=Fh=mgh=50kg15m9.8ms2=7350J.W = Fh = mgh = 50 kg \cdot 15 m \cdot 9.8 \dfrac{m}{s^2} = 7350 J.

b) We can find the power from the formula:


P=Wt=7350J5min60s1min=24.5W.P = \dfrac{W}{t} = \dfrac{7350 J}{5 min \cdot \dfrac{60 s}{1 min}} = 24.5 W.

Answer:

a) W=7350J.W = 7350 J.

b) P=24.5W.P = 24.5 W.


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