Question #86088

I am a safety supervisor for an oil company. I need to know what is the force generated by an unsecured 300lb drum of oil traveling at 30mph if the truck stops suddenly. I am trying to instruct drivers about securing their loads and what can happen if they don't secure the load. For example: The 300lb drum would generate an impact force = to 1500lbs if the truck was traveling at 30 mph??? What about 50mph??? 2500 lbs of force????
Can you help me with these calculations?

Thanks,

Steve

Expert's answer

It's quite easy to calculate the force applying Newton's second law:


F=maF=ma

and the formula for acceleration in terms of braking time and braking distance:


a=2dt2.a=\frac{2d}{t^2}.

Thus the impact force will be


F=m⋅2dt2.F=m\cdot \frac{2d}{t^2}.

On the other hand, you can use the same law but substitute the acceleration expressed in terms of speed and braking distance:


F=m⋅vfinal2−vinitial22d.F=m\cdot\frac{v^2_{final}-v^2_{initial}}{2d}.

Also, expressing the acceleration through velocities and the time required to slow the truck down from vinitialv_{initial} to vfinalv_{final}:


F=m⋅vfinal−vinitialt.F=m\cdot\frac{v_{final}-v_{initial}}{t}.

Remember that to determine the force in Newtons, use m/s for speed, meters and seconds.


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