Question #85943
The New York Ferry (m = 13000.0 kg loaded) is travelling at 11 m/s when the engines are put in reverse. The engine produces a force of 1.0 x 106 N for a period of 20.0 seconds.
1
Expert's answer
2019-03-07T11:24:49-0500

Too much force for so light ferry. Assume its mass is 13 000 000 kg. With this information we can calculate for example:

  • The magnitude of the momentum from the engine:
Δp=FΔt=2107 kgm/s.\Delta p=F\Delta t=2\cdot 10^7 \text{ kg}\cdot\text{m/s}.


  • The new momentum of the ferry:
p1=p0Δp=mv0Δp=p_1=p_0-\Delta p=mv_0-\Delta p==13000000112107=123000000 kgm/s.=13000000\cdot 11-2\cdot 10^7=123000000\text{ kg}\cdot\text{m/s}.


  • The new velocity of the ferry:
v1=p1/m=9.46 m/s.v_1=p_1/m=9.46\text{ m/s}.


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