Answer to Question #84057 in Mechanics | Relativity for hanna

Question

A 10 newton force acts on an object for 0.01 seconds. What force, acting on the object for 0.05 seconds, would produce the same impulse?

Answer 1

By the definition of the impulse, we get:

$J = F∆t,$

here,

$J$

is the impulse,

$F$

is the force acting on the object and

$∆t$

is the time interval at which the force acts on the object.

Then, from this formula we can find the impulse which produced by the

$10 N$

force acting on the object for 0.01 seconds:

$J = F∆t = 10 N \cdot 0.01 s = 0.1 N \cdot s.$

Then, the time at which the force acts on the object was change to 0.05 seconds. The force , acting on the object can be found from the same formula:

$F = \frac{J}{∆t} = \frac{0.1 N \cdot s}{0.05 s} = 2 N.$

Answer:

$F = 2 N$

.