Question #55640

The resulting temperature when 1kg of ice at 0 degrees Celcius is mixed with 9kg of water at 50 degress Celcius is ----------------------- to the nearest whole number.The specific capacity of water is 4200J/kg/K,the specific latent heat of fusion of ice is 330 000J/kg

A. 24 degreees celcius
B. 37 degreees celcius
C. 46 degreees celcius
D. 56 degreees celcius
1

Expert's answer

2015-11-07T00:00:48-0500

Answer on Question #55640-Physics-Mechanics-Relativity

The resulting temperature when 1kg of ice at 0 degrees Celsius is mixed with 9kg of water at 50 degrees Celsius is --- to the nearest whole number. The specific capacity of water is 4200J/kg/K, the specific latent heat of fusion of ice is 330 000J/kg

A. 24 degrees Celsius

B. 37 degrees Celsius

C. 46 degrees Celsius

D. 56 degrees Celsius

Solution

Let the final temperature of the water be xx and imagine that there is sufficient energy to melt all the ice so that x>0x > 0.

The ice requires 330000 J to melt plus 4200x4200 \cdot x to raise the temperature to xx.

This energy comes from cooling the remainder of the water:

mass · temperature change · specific heat = 9(50 - x)4200;

Hence


330000+4200x=9(50x)4200.330000 + 4200 \cdot x = 9(50 - x)4200.


Now solve


330000+4200x=45042009x4200330000 + 4200x = 450 \cdot 4200 - 9x \cdot 4200x=4504200330000104200=37C.x = \frac{450 \cdot 4200 - 330000}{10 \cdot 4200} = 37{}^{\circ} \mathrm{C}.


Answer: B. 37 degrees Celsius.

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