Question #55636

In a simple pendulum experiment,  T2/s2
is plotted on the vertical axis while ------------- is plotted on the horizontal axis

A. l2/m2
B. 1/lcm-1
C. l/cm
D. logl
1

Expert's answer

2015-11-03T00:00:47-0500

Answer on Question #55636, Physics / Mechanics | Relativity

In a simple pendulum experiment, T2/s2T^2 / s^2 is plotted on the vertical axis while --- is plotted on the horizontal axis

A. I2/m2I^2 / m^2

B. 1/Icm11 / I \, \text{cm}^{-1}

C. I/cmI / \text{cm}

D. logI

Solution:

The period of a simple pendulum can be found by


T=2πlgT = 2 \pi \sqrt {\frac {l}{g}}


Therefore, for small amplitudes the period of a simple pendulum depends only on its length and the value of the acceleration due to gravity.

If both sides of Equation are squared then


T2=4π2lgT^2 = \frac{4 \pi^2 l}{g}


A graph of T2T^2 versus ll should result in a straight line.

The period squared is the dependent variable and should be plotted on the y axis. The length is the independent variable and should be plotted on the x axis.

Answer: C. $I / \text{cm}$

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