Question

A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 90.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 450 N. What force does the motorcycle exert backward on the ground to produce its acceleration if its mass with rider is 240 kg?

Answer 1

Question #53228, Physics / Mechanics | Kinematics | Dynamics |

A powerful motorcycle can produce an acceleration of $3.00 \, \text{m/s}^2$ while traveling at $90.0 \, \text{km/h}$. At that speed, the forces resisting motion, including friction and air resistance, total 450 N. What force does the motorcycle exert backward on the ground to produce its acceleration if its mass with rider is 240 kg?

Answer:

The force which pulls the motorcycle forward is defined according the second Newton law:

$$F = a \times m$$

where $a$ – acceleration, and $m$ – the mass with rider.

Thus, $F = 3 \, \text{m/s}^2 \times 240 \, \text{kg} = 720 \, \text{N}$

Since the forces resisting motion exert in opposite direction to this, the total force exerting backward on the ground equals:

$$F_t = F + F_r$$

where $F_r$ – the forces resisting motion.

Then $F_t = 720 \, \text{N} + 450 \, \text{N} = 1170 \, \text{N}$

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