Question #53146

Which physics formulas do I need to focus on to determine whether or not an amusement park swing ride rotating at its max speed can hold a 50 lb. child safely if, while stationary, the swing can hold up a 200 lb. man? Is the centripetal force what I am supposed to be finding, and then I compare it to the stationary hanging tension when the 200 lb. weight is on it?
1

Expert's answer

2015-06-25T02:45:06-0400

Answer on Question#53146 - Physics - Mechanics - Kinematics - Dynamics

Which physics formulas do I need to focus on to determine whether or not an amusement park swing ride rotating at its max speed can hold a m=50m = 50 lb. child safely if, while stationary, the swing can hold up a M=200M = 200 lb. man? Is the centripetal force what I am supposed to be finding, and then I compare it to the stationary hanging tension when the 200 lb. weight is on it?

Solution:

Actually, you should consider the (vector) sum of centrifugal force FcF_{c} and the force due to gravity mgmg . This sum should be balanced by the tension TT of the rope or chain of the swing. The magnitude of this tension force should be equal to the weight of the 200 lb. man.



The magnitude of the centrifugal force is given by


Fc=mω2r,F _ {c} = m \omega^ {2} r,


where ω\omega - is the angular frequency of the swing's rotation. Therefore the magnitude of the tension force is given by


T=(mg)2+Fc2=mg2+ω4r2T = \sqrt {(m g) ^ {2} + F _ {c} ^ {2}} = m \sqrt {g ^ {2} + \omega^ {4} r ^ {2}}


If the length of the rope is ll then due to similarity we obtain


TFc=lr\frac {T}{F _ {c}} = \frac {l}{r}g2+ω4r2ω2r=lr\frac {\sqrt {g ^ {2} + \omega^ {4} r ^ {2}}}{\omega^ {2} r} = \frac {l}{r}r=l2g2ω4r = \sqrt {l ^ {2} - \frac {g ^ {2}}{\omega^ {4}}}


Therefore the tension force is


T=mg2+ω4(l2g2ω4)=mω2lT = m \sqrt {g ^ {2} + \omega^ {4} \left(l ^ {2} - \frac {g ^ {2}}{\omega^ {4}}\right)} = m \omega^ {2} l


To determine whether or not the swing rotating at its max speed can hold a child you should substitute angular frequency into the previous expression and compare it with the weight of the man MgMg . If it's greater than the man's weight the swing may not hold the child, if not then the swing will hold the child.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS