Question #51366

You are arguing over a cell phone while trailing an unmarked police car by 26.0 m; both your car and the police car are traveling at 120 km/h. Your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell,“I won't do that!”). At the beginning of that 2.0 s, the police officer begins braking suddenly at 5.20 m/s^2. (a) What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.500 s to realize your danger and begin braking. (b) If you too brake at 5.20 m/s^2, what is your speed when you hit the police car?
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Expert's answer

2015-03-20T03:04:27-0400

Question

You are arguing over a cell phone while trailing an unmarked police car by 26.0m26.0 \, \text{m}; both your car and the police car are traveling at 120km/h120 \, \text{km/h}. Your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell, "I won't do that!"). At the beginning of that 2.0 s, the police officer begins braking suddenly at 5.20m/s25.20 \, \text{m/s}^2. (a) What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.500 s to realize your danger and begin braking. (b) If you too brake at 5.20m/s25.20 \, \text{m/s}^2, what is your speed when you hit the police car?

Solution

a) l=26m;v01=v02=v=120km/h33.333m/s;t=2s,a1=0;a2=a=5.2m/s2l = 26 \, \text{m}; \quad v_{01} = v_{02} = v = 120 \, \text{km/h} \approx 33.333 \, \text{m/s}; \quad t = 2 \, \text{s}, \quad a_1 = 0; \quad a_2 = a = 5.2 \, \text{m/s}^2.



Our car: x1=v01t=vtx_{1} = v_{01}t = vt.

Police car: x2=lv02t+a2t2/2=lvt+at2/2x_{2} = l - v_{02}t + a_{2}t^{2}/2 = l - vt + at^{2}/2.

The separation between the two cars: Δx=x2x1=l2vt+at2/2=96.932m\Delta x = x_{2} - x_{1} = l - 2vt + at^{2}/2 = -96.932 \, \text{m}.

It means that cars hit before end of 2 s. Answer: Δx=0\Delta x = 0.

b) The speed of our car is 33.333m/s33.333 \, \text{m/s}, because we can't return our attention (cars hit before end of 2 s). Answer: v=v01=120km/h33.333m/sv = v_{01} = 120 \, \text{km/h} \approx 33.333 \, \text{m/s}.

P.S. I guess condition of the problem contain mistake. I think initial separation between the two cars is bigger. Please check it and if you want write me back, I'll do it again.

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