Question #51365, Physics, Mechanics | Kinematics | Dynamics
A car traveling 54.3 km/h is 24.3 m from a barrier when the driver slams on the brakes. The car hits the barrier 2.14 s later. (a) What is the car's constant deceleration magnitude before impact? (b) How fast is the car traveling at impact?
Answer.
S=V0t−2at2, V=V0−at.
In our case:
S=24.3 m, V0=54.3 hkm=54.3 ∗60 ∗601000=15.08 sm, t=2.14 s.
(a) a=t22(Vt−S)=2.1422(15.08∗2.14−24.3)=3.48 s2m
(b) V=15.08−3.48∗2.14=7.63 sm
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