Question #50001

The period T (time for one complete oscillation) for a simple pendulum is related to the length l of the pendulum by the relationship T = 2π√l/g where g is the acceleration of free fall. Find,
a) What apparatus you need to perform this experiment.
b) Explain the theory, readings and the graph to be drawn to find g.
c) Explain the procedure of the experiment.
d) What steps have to be taken to minimize the errors of the experiment?
1

Expert's answer

2014-12-22T09:24:15-0500

Answer on Question # 50001 – Physics – Mechanics | Kinematics | Dynamics

Given: Pendulum, the period T=2πlgT = 2\pi \sqrt{\frac{l}{g}}

Solution:

a) a pendulum consists of

1) weightless thread

2) load

also we need to have some stop-watch

b) tAB=2lgg=4ltAB2t_{AB} = 2\sqrt{\frac{l}{g}} \Rightarrow g = \frac{4l}{t_{AB}^2}

where tABt_{AB} is a time of motion of the load from A to B.

c) at first we have to deviate the load to the maximum angle of deviation. Then we let go the thread and write down the time for one complete oscillation.

d) So the approximate solution


T=4tAB=8lgT = 4 t _ {A B} = 8 \sqrt {\frac {l}{g}}


but the exact solution


T=2πlgT = 2 \pi \sqrt {\frac {l}{g}}


Steps to minimize the errors of the experiment

1. to increase the amount of measuring

2. to change the angle of deviation

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