Question

An object of 2 kg released from a height of 80 m falls on a soft ground and comes to rest after penetrating to a depth of 20 cm. Calculate the force offered by the ground.

Answer 1

Answer on Question 49994, Physics, Mechanics — Kinematics — Dynamics An object of 2 kg released from a height of 80 m falls on a soft ground and comes to rest after penetrating to a depth of 20 cm. Calculate the force offered by the ground.

Solution

We will use energy conservation law here. Potential energy of object $mgh$ at the beginning is equal to work done, during penetrating the ground. Hence

$mgh=F\Delta l$

$F=\frac{mgh}{\Delta l}=\frac{2\cdot 9.8\cdot 80}{0.2}\approx 7840\,N$

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