Question

A ball of mass 100g strikes a wall with the speed 2m/s and the bounces off the wall in the opposite direction with the same speed calculate the impulse of the ball

Answer 1

Impulse moment theorem

$∆I=∆P=m(u-v)$

$u=2m/sec\\v=-2m/sec$

Put value

$$∆I=0.1\times(2-(-2))=0.1\times4=0.4kgm /sec$$