A ball of mass 100g strikes a wall with the speed 2m/s and the bounces off the wall in the opposite direction with the same speed calculate the impulse of the ball
Impulse moment theorem
∆I=∆P=m(u−v)∆I=∆P=m(u-v)∆I=∆P=m(u−v)
u=2m/secv=−2m/secu=2m/sec\\v=-2m/secu=2m/secv=−2m/sec
Put value
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