Question #297634

A ball of mass 100g strikes a wall with the speed 2m/s and the bounces off the wall in the opposite direction with the same speed calculate the impulse of the ball

1
Expert's answer
2022-02-14T14:23:24-0500

Impulse moment theorem

I=P=m(uv)∆I=∆P=m(u-v)

u=2m/secv=2m/secu=2m/sec\\v=-2m/sec

Put value


I=0.1×(2(2))=0.1×4=0.4kgm/sec∆I=0.1\times(2-(-2))=0.1\times4=0.4kgm /sec


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