For the velocity potential function, ϕ = x ^ 2 - y ^ 2 find the velocity components at the point (4, 5)
ϕ=x2−y2\phi=x^2-y^2ϕ=x2−y2
Point (4,5)
We know that
ux=dϕdt=2xu_x=\frac{d\phi}{dt}=2xux=dtdϕ=2x
uy=dϕdt=−2yu_y=\frac{d\phi}{dt}=-2yuy=dtdϕ=−2y
ux=2×2=4u_x=2\times2=4ux=2×2=4
uy=−2×5=−10u_y=-2\times5=-10uy=−2×5=−10
Velocity
∣v∣=10.77|v|=10.77∣v∣=10.77
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments