Question #273276

An ideal Stirling engine with air as the working fluid is considered. The temperature of the source-energy reservoir, the amount of air contained in the engine, and the maximum air pressure during the cycle are to be determined.

Assumptions: Air is an ideal gas with constant specific heats. Properties: The properties of air at room temperature are R = 0.3704 psia·ft3 /lbm.R, cp = 0.240 Btu/lbm·R, cv = 0.171 Btu/lbm·R, and k = 1.4.


1
Expert's answer
2021-11-30T09:49:56-0500


From the thermal efficiency relation

ηth=WnetQin=1TLTH    2.56=1510TH    TH=874\eta_{th}=\frac{W_{net}}{Q_{in}}=1-\frac{T_L}{T_H}\implies \frac{2.5}{6}=1-\frac{510}{T_H}\implies T_H=874 R


State 3 may be used to determine the mass of air in the system:

m=P3V3RT3=100.50.3704510=0.02647m=\frac{P_3V_3}{RT_3}=\frac{10\cdot0.5}{0.3704\cdot510}=0.02647 lbm


The maximum pressure occurs at state 1:

P1=mRT1V1=0.026470.37048740.06=143P_1=\frac{mRT_1}{V_1}=\frac{0.02647\cdot0.3704\cdot874}{0.06}=143 psia


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