Question

The curve of a 70.0-m circular path is banked at 35O. At what velocity shall a 1000- kg car have for it to make the turn in this curve? 

Answer 1

reaction of road in x-direction:

$N=mgcos10\degree sin10\degree$

then:

$N=mv^2/R$

$v=\sqrt{RN/m}=\sqrt{gRcos10\degree sin10\degree}=\sqrt{70gcos10\degree sin10\degree}=10.83$ m/s