three particles of the respective masses m1-12kg,m2-24kg, and m3-36kg formed an equilateral triangle of side length a=120cm.If we locate m1 at the origin of the xy-plane and put m2 to right of m1 at right axis.What is the approximate coordinate s of the center of the mass of the system?
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Expert's answer
2021-11-26T11:53:18-0500
The center of mass of the system is m1=12kgm2=24kgm3=36kga=0.12m
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