Question #256096

On a frictionless horizontal air table, puck A (mass 0.246 kg) is moving to the right toward puck B (mass 0.667 kg), which is initially at rest. Puck A collides inelastically with puck B. After the collision, puck A has velocity 0.207 m/s to the left, and puck B has velocity 0.532 m/s to the right.

  1. What was the speed of puck A before the collision?
  2. Calculate the initial kinetic energy of puck A.
  3. Calculate the change in total kinetic energy of the system that occurs during the collision.

Expert's answer

1) Use momentum conservation:


mv=mvm+MvM,v=1.235 m/s.mv=-mv_m+Mv_M,\\ v=1.235\text{ m/s}.

2) The initial energy:


Ke=0.5mv2=0.188 J.Ke=0.5mv^2=0.188\text{ J}.

3) The change is the difference between the initial energy and final energies of both pucks:


=KeKemKeM=0.0883 J.∆=Ke-Ke_m-Ke_M=0.0883\text{ J}.


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