Question #253942

A box with a mass of 50 kg is shoved by a man across the floor with a force of 100 N through a distance of 5 m. He then shoves it up a 300 inclined to a height of 1 m by exerting a force equal to 3/5 its weight. What is the final potential energy of the box?


1
Expert's answer
2021-10-24T18:19:31-0400

The final potential energy of the box depends on its height (position) only:


E=mgh,E=509.81sin30°=245 J.E=mgh,\\ E=50\cdot9.8\cdot1\cdot\sin30°=245\text{ J}.


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