A rock is thrown horizontally from the top of a building with an initial speed of v = 10.1 m/s. If it lands d = 57.1 m from the base of the building, how high is the building?
The speed in horizontal direction remains unchanged during the falling. Thus, the time of falling is given as follows:
where is the range, and is the horizontal speed.
The distance travelled in vertical direction (height of the building) is given by the following kinematic equation:
where is the gravitational acceleration. Substituting the expression for , obtain:
Answer. 157 m.
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