(a) A merry-go-round with 5 m radius is rotating around its vertical axis with a rate of 0.30 rev/s. A 90 kg man jump on to the merry-go-round and he lands and remains at a distance of 3 m from the axis of rotation. If the moment of inertia of the merry-go-round is 10,000
kgm2, find the new rate of rotation after the person has landed.
The same merry-go-round mentioned in the part (a) is at rest and a 90 kg man is standing at the edge of the merry-go-round. Then he starts to walk around the perimeter at a speed of 0.8 m/s relative to the ground. What rotation rate does this motion give to the merry-go-round?
Given:
(a) The law of conservation of angular momentum says
Hence
(b)
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