"F = 3.0\\,\\mathrm{N}, \\;\\\\ S = 0.60\\,\\mathrm{cm}^2 = 0.60\\cdot10^{-4}\\,\\mathrm{m}^2 = 6\\cdot10^{-5}\\,\\mathrm{m}^2"
We don't know the angle between the direction of the force and the normal to the piston. If the angle is "\\alpha" then the pressure will be
"p = \\dfrac{F\\cos\\alpha}{S}" , so the greatest pressure will correspond to "\\alpha = 0", so the greatest pressure will be
"p = \\dfrac{F}{S} = \\dfrac{3.0\\,\\mathrm{N}}{6\\cdot10^{-5}\\,\\mathrm{m}^2} = 5\\cdot10^4\\,\\mathrm{Pa}."
Comments
Leave a comment