Question #216903

The contraption below has the following characteristics: m1 = 2.0 x 10^3 kg, m2 = 4.4 x 10^2 kg, the man on top of m2 has a mass m = 6.0 x 10^1 kg, and all surfaces are frictionless. What is the apparent weight of the man?


1
Expert's answer
2021-07-13T11:52:49-0400

Gives

m1=2.0×103kgm2=4.4×102kgm=6.0×101kgm_1=2.0\times10^3kg\\m_2=4.4\times10^2kg\\m=6.0\times10^1kg

g=9.8m/sec2g=9.8m/sec^2

We know that

W=mgW=mg

Put value

W=6.0×101×9.8=588NW=6.0\times10^1\times9.8=588N


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