Answer to Question #198772 in Mechanics | Relativity for karen

Question #198772

A mass of 100 kg is being pushed along the floor at a constant velocity of 2 m/s. If the coefficient of kinetic friction is 0.25, at what rate is work (power) being done in watts, in horsepower?


1
Expert's answer
2021-05-26T13:02:54-0400


Gives

Mass(m)=100kg

μ=0.25\mu=0.25

Velocity (v)=2m/secm/sec

F=μR=μmgF=\mu R=\mu mg

F=0.25×100×9.8=245N0.25\times100\times 9.8=245N

Power

P=F.vP=F.v

dWdt=P=245×2cos0°\frac{dW}{dt}=P=245\times2\cos0°

dWdt=P=490W\frac{dW}{dt}=P=490W

dWdt=P=490746hp=0.6568hp\frac{dW}{dt}=P=\frac{490}{746} hp=0.6568hp

1 hp=746W

P=dWdt=0.6568hpP=\frac{dW}{dt}=0.6568hp


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